题目：原题链接（中等）
标签：多线程
解法 | 时间复杂度 | 空间复杂度 | 执行用时 |
Ans 1 (Python) | O ( N ) | O ( 1 ) | 56ms (33.33%) |
Ans 2 (Python) | |||
Ans 3 (Python) |
解法一：
class H2O:
def __init__(self):
self.count = 0
self.s1 = threading.Semaphore(2)
self.s2 = threading.Semaphore(0)
def hydrogen(self, releaseHydrogen: 'Callable[[], None]') -> None:
self.s1.acquire()
releaseHydrogen()
self.count += 1
if self.count == 2:
self.s2.release()
self.count = 0
def oxygen(self, releaseOxygen: 'Callable[[], None]') -> None:
self.s2.acquire()
releaseOxygen()
self.s1.release()
self.s1.release()
