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303. Range Sum Query - Immutable

幺幺零 2022-12-01 阅读 172


nums, find the sum of the elements between indices i and j (i ≤ j), inclusive.

Example:


Given nums = [-2, 0, 3, -5, 2, -1] sumRange(0, 2) -> 1 sumRange(2, 5) -> -1 sumRange(0, 5) -> -3


Note:

  1. You may assume that the array does not change.
  2. There are many calls to sumRange

class NumArray {
public:
NumArray(vector<int> &nums) {
int sum = 0;
int len = nums.size();
for (int i = 0; i < len; i++){
sum += nums[i];
subSum.push_back(sum);
}
}

int sumRange(int i, int j) {
if (i == 0){
return subSum[j];
}
else{
return subSum[j] - subSum[i - 1];
}
}

vector<int>subSum;
};



// Your NumArray object will be instantiated and called as such:
// NumArray numArray(nums);
// numArray.sumRange(0, 1);
// numArray.sumRange(1, 2);




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