Python 根据弧度和半径求弧长

l = A * np.pi * R / 180

karc = math.atan(k)
kangle = math.degrees(karc)

def solveKB(x1, y1, x2, y2):
    k = (y2 - y1) / (x2 - x1)
    b = y1 - k * x1
    return k, b

def solveB(k, b):
    b = sqrt((R * k) ** 2 + R ** 2) + b
    return b

def solveXY(k1, b1, k2, b2):
    X = solve((k1 * x + b1) - (k2 * x + b2), x)[0]
    Y = k1 * X + b1
    return X, Y