四数之和
解法一:双指针法
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
public class Solution {
public static List<List<Integer>> fourSum(int[] nums, int target) {
if (nums == null || nums.length < 4) {
return new ArrayList<>();
}
if (nums.length == 4 && nums[0] + nums[1] + nums[2] + nums[3] != target) {
return new ArrayList<>();
}
Arrays.sort(nums);
List<List<Integer>> result = new ArrayList<>();
for (int first = 0, fourth = nums.length - 1; first < fourth - 2; first++) {
// 过滤掉重复的
if (first > 0 && nums[first] == nums[first - 1]) {
continue;
}
while (first < fourth - 2) {
// 过滤掉重复的
if (fourth < nums.length - 1 && nums[fourth] == nums[fourth + 1]) {
fourth--;
continue;
}
for (int second = first + 1, third = fourth - 1; second < third; second++) {
// 过滤掉重复的
if (second > first + 1 && nums[second] == nums[second - 1]) {
continue;
}
while (second < third && nums[first] + nums[second] + nums[third] + nums[fourth] > target) {
third--;
}
if (second != third && nums[first] + nums[second] + nums[third] + nums[fourth] == target) {
result.add(new ArrayList<>(Arrays.asList(new Integer[]{nums[first], nums[second], nums[third], nums[fourth]})));
}
}
fourth--;
}
fourth = nums.length - 1;
}
return result;
}
public static void main(String[] args) {
int[] nums = new int[]{-3, -1, 0, 2, 4, 5};
for (List<Integer> integers : fourSum(nums, 0)) {
for (Integer integer : integers) {
System.out.print(integer + "/");
}
System.out.println();
}
}
}
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