public int minPathSum(int[][] grid) {
int m=grid.length;
int n=grid[0].length;
int[][] dp=new int[m][n];//表示到达(i,j)的最小路径和
//初始化
dp[0][0]=grid[0][0];
for (int i = 1; i < m; i++) {
dp[i][0]=dp[i-1][0]+grid[i][0];
}
for (int i = 1; i < n; i++) {
dp[0][i]=dp[0][i-1]+grid[0][i];
}
//dp[i][j]等于dp[i][j-1]和dp[i-1][j]中的较小值+自身值
for (int i = 1; i < m; i++) {
for (int j = 1; j < n; j++) {
dp[i][j]=Math.min(dp[i][j-1],dp[i-1][j])+grid[i][j];
}
}
return dp[m-1][n-1];
}