字母异位词分组
解法一:Hash判重
import java.util.*;
public class LeetCode_049 {
public static List<List<String>> groupAnagrams(String[] strs) {
Map<String, List<String>> tempResult = new HashMap<>();
for (String str : strs) {
char[] chars = str.toCharArray();
Arrays.sort(chars);
String sortedStr = String.valueOf(chars);
if (tempResult.get(sortedStr) == null) {
List<String> values = new ArrayList<>();
values.add(str);
tempResult.put(sortedStr, values);
} else {
tempResult.get(sortedStr).add(str);
}
}
List<List<String>> result = new ArrayList<>();
result.addAll(tempResult.values());
return result;
}
public static void main(String[] args) {
String[] strs = new String[]{"eat", "tea", "tan", "ate", "nat", "bat"};
List<List<String>> lists = groupAnagrams(strs);
for (List<String> list : lists) {
for (String s : list) {
System.out.print(s + " ");
}
System.out.println();
}
}
}