题目:原题链接(中等)
标签:字符串
解法 | 时间复杂度 | 空间复杂度 | 执行用时 |
Ans 1 (Python) | O(N) | O(N) | 56ms (84.40%) |
Ans 2 (Python) | |||
Ans 3 (Python) |
LeetCode的Python执行用时随缘,只要时间复杂度没有明显差异,执行用时一般都在同一个量级,仅作参考意义。
解法一:
class Solution:
def expressiveWords(self, S: str, words: List[str]) -> int:
def change(s):
exp = []
for ch in s:
if not exp or ch != exp[-1][0]:
exp.append([ch, 1])
else:
exp[-1][1] += 1
return exp
S = change(S)
N = len(S)
ans = 0
for word in words:
word = change(word)
if len(word) == N:
for i in range(N):
if word[i][0] != S[i][0] or word[i][1] > S[i][1] or (word[i][1] == 1 and S[i][1] == 2):
break
else:
ans += 1
return ans