0
点赞
收藏
分享

微信扫一扫

你不知道的那些事(一)——128陷阱

嚯霍嚯 2022-01-15 阅读 56
java128

引言

具体事例

public class Test {
    public static void main(String[] args) {
        Integer a1=127;
        Integer a2=127;
        Integer b1=128;
        Integer b2=128;
        System.out.println(a1==a2);
        System.out.println(b1==b2);
    }
}

请问输出是什么?

no no no!!!你看到的只是表象,其实里面还有小秘密哦!!!
输出的结果如下:
在这里插入图片描述
是不是有点不可思议!

剖析原因

请看源码

/**
     * Cache to support the object identity semantics of autoboxing for values between
     * -128 and 127 (inclusive) as required by JLS.
     *
     * The cache is initialized on first usage.  The size of the cache
     * may be controlled by the {@code -XX:AutoBoxCacheMax=<size>} option.
     * During VM initialization, java.lang.Integer.IntegerCache.high property
     * may be set and saved in the private system properties in the
     * sun.misc.VM class.
     */

    private static class IntegerCache {
        static final int low = -128;
        static final int high;
        static final Integer cache[];

        static {
            // high value may be configured by property
            int h = 127;
            String integerCacheHighPropValue =
                sun.misc.VM.getSavedProperty("java.lang.Integer.IntegerCache.high");
            if (integerCacheHighPropValue != null) {
                try {
                    int i = parseInt(integerCacheHighPropValue);
                    i = Math.max(i, 127);
                    // Maximum array size is Integer.MAX_VALUE
                    h = Math.min(i, Integer.MAX_VALUE - (-low) -1);
                } catch( NumberFormatException nfe) {
                    // If the property cannot be parsed into an int, ignore it.
                }
            }
            high = h;

            cache = new Integer[(high - low) + 1];
            int j = low;
            for(int k = 0; k < cache.length; k++)
                cache[k] = new Integer(j++);

            // range [-128, 127] must be interned (JLS7 5.1.7)
            assert IntegerCache.high >= 127;
        }

分析源码:

回到事例中,由于a1、a2都等于127,而127存储在常量池中的cache数组中,也就是说,a1和a2指向同一个地址,因此为 true 。
而b1和b2都为128,不再数组范围之内,因此需给它们开辟不同的“家”。地址不同,因此 false。

你学会了吗?

举报

相关推荐

0 条评论