LeetCode530. Minimum Absolute Difference in BST

文章目录

• • 一、题目
  • 二、题解

一、题目

Given the root of a Binary Search Tree (BST), return the minimum absolute difference between the values of any two different nodes in the tree.

Example 1:

Input: root = [4,2,6,1,3]
Output: 1
Example 2:

Input: root = [1,0,48,null,null,12,49]
Output: 1

Constraints:

The number of nodes in the tree is in the range [2, 104].
0 <= Node.val <= 105

Note: This question is the same as 783: https://leetcode.com/problems/minimum-distance-between-bst-nodes/

二、题解

中序遍历+双指针

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
public:
    int res = INT_MAX;
    TreeNode* pre = nullptr;
    //中序遍历，比较两个指针的差值
    void traversal(TreeNode* cur){
        if(!cur) return;
        traversal(cur->left);
        if(pre) res = min(res,cur->val - pre->val);
        pre = cur;
        traversal(cur->right);
    }
    int getMinimumDifference(TreeNode* root) {
        traversal(root);
        return res;
    }
};