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Spring_使用XML配置文件创建对象

朱悟能_9ad4 2022-07-27 阅读 58


<beans>
<bean id="u" class="com.bjsxt.dao.impl.UserDaoImpl" />

<!--
<bean id="userService" class="com.bjsxt.service.UserService">
<property name="userDao" bean="u" />
</bean>
-->
</beans>


package com.bjsxt.spring;

public interface BeanFactory {
public Object getBean(String name);
}


package com.bjsxt.spring;

import java.util.HashMap;
import java.util.List;
import java.util.Map;

import org.jdom2.Document;
import org.jdom2.Element;
import org.jdom2.input.SAXBuilder;

public class ClassPathXmlApplicationContext implements BeanFactory {
private Map<String, Object> beans = new HashMap<String, Object>();

public ClassPathXmlApplicationContext() throws Exception {
SAXBuilder sb = new SAXBuilder();
Document document = sb.build(ClassPathXmlApplicationContext.class
.getClassLoader().getResource("beans.xml"));// 获取文件
Element root = document.getRootElement();// 获取根元素
List list = root.getChildren();// 获取名字为bean的所有元素(子元素)
for (int i = 0; i < list.size(); i++) {
Element element = (Element) list.get(i);
String id = element.getAttributeValue("id");
String clazz = element.getAttributeValue("class");
System.out.println(id + ":" + clazz);
Object obj = Class.forName(clazz).newInstance();
beans.put(id, obj);
}
}

@Override
public Object getBean(String name) {
return beans.get(name);
}

}


package com.bjsxt.service;

import org.junit.Test;

import com.bjsxt.dao.UserDao;
import com.bjsxt.model.User;
import com.bjsxt.spring.BeanFactory;
import com.bjsxt.spring.ClassPathXmlApplicationContext;

public class UserServiceTest {

@Test
public void testAdd() throws Exception {
BeanFactory factory = new ClassPathXmlApplicationContext();

UserService service = new UserService();
UserDao ud = (UserDao) factory.getBean("u");
service.setUd(ud);
User user = new User();
service.add(user);
}

}



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