Description
Farmer John goes to Dollar Days at The Cow Store and discovers an unlimited number of tools on sale. During his first visit, the tools are selling variously for $1, $2, and $3. Farmer John has exactly $5 to spend. He can buy 5 tools at $1 each or 1 tool at $3 and an additional 1 tool at $2. Of course, there are other combinations for a total of 5 different ways FJ can spend all his money on tools. Here they are:
1 @ US$3 + 1 @ US$2 1 @ US$3 + 2 @ US$1 1 @ US$2 + 3 @ US$1 2 @ US$2 + 1 @ US$1 5 @ US$1
Input
A single line with two space-separated integers: N and K.
Output
A single line with a single integer that is the number of unique ways FJ can spend his money.
Sample Input
5 3
Sample Output
5
多重背包+高精度
dp【i】=dp【i-1】+dp【i-j】
#include<cstdio>
#include<iostream>
#include<algorithm>
#include<cstring>
using namespace std;
#define N 50010
long long int inf,b[N],a[N];
int main()
{
long long int n,m,i,j;
for(inf=1,i=1;i<18;i++) inf*=10;
scanf("%lld %lld",&m,&n);
memset(a,0,sizeof(a));
memset(b,0,sizeof(b));
a[0]=1;
for(i=1;i<=n;i++)
{
for(j=i;j<=m;j++)
{
b[j]=b[j]+b[j-i]+(a[j]+a[j-i])/inf;
a[j]=(a[j]+a[j-i])%inf;
}
}
if(b[m]) cout<<b[m];
cout<<a[m]<<endl;
return 0;
}