题目:
1.创建数据库
create database if not exists db2 ;
2.创建表
1.创建学生表
drop table if exists student;
create table student
(
id varchar(10) comment '学号',
name varchar(10) NOT NULL comment '姓名',
gender char(1) comment '性别',
class varchar(20) comment '专业班级',
date date comment '出生日期',
iphone varchar(11) comment '联系电话'
)
comment '学生表';
select * from student;
2.创建课程表
drop table if exists student_course;
create table student_course
(
course_id varchar(10) comment '课程号',
course_name varchar(15) comment '课程名',
course_number double unsigned comment '学分数',
student_time int unsigned comment '学时数',
teacher varchar(10) comment '任课教师'
)
comment '课程表';
select *
from student_course;
3.学生作业表
drop table if exists student_homework;
create table student_homework
(
course_id varchar(10) comment '课程号',
id varchar(10) comment '学号',
homework_1 int comment '作业1成绩',
homework_2 int comment '作业2成绩',
homework_3 int comment '作业3成绩'
)
comment '学生作业表';
select *
from student_homework;
3.添加数据
1.学生表
insert into student
values ('0433', '张艳', '女', '生物04', '1986-9-13', null),
('0496', '李越', '男', '电子04', '1984-2-23', '1381290xxxx'),
('0529', '赵欣', '男', '会计05', '1984-1-27', '1350222xxxx'),
('0531', '张志国', '男', '生物05', '1986-9-10', '1331256xxxx'),
('0538', '于兰兰', '女', '生物05', '1984-2-20', '1331200xxxx'),
('0591', '王丽丽', '女', '电子05', '1984-3-20', '1332080xxxx'),
('0592', '王海强', '男', '电子05', '1986-11-1', null);
查询一下:
select * from student;
2.课程表
INSERT INTO student_course
values ('K001', '计算机图形学', 2.5, 40, '胡晶晶'),
('K002', '计算机应用基础', 3, 48, '任泉'),
('K006', '数据结构', 4, 64, '马跃先'),
('M001', '政治经济学', 4, 64, '孔繁新'),
('S001', '高等数学', 3, 48, '赵晓尘');
查询一下:
select *
from student_course;
3.学生作业表
insert into student_homework values
('K001','0433',60,75,75),
('K001','0529',70,70,60),
('K001','0531',70,80,80),
('K001','0591',80,90,90),
('K002','0496',80,80,90),
('K002','0529',70,70,85),
('K002','0531',80,80,80),
('K002','0538',65,75,85),
('K002','0592',75,85,85),
('K006','0531',80,80,90),
('K006','0591',80,80,80),
('M001','0496',70,70,80),
('M001','0591',65,75,75),
('S001','0531',80,80,80),
('S001','0538',60,null,80);
查询一下:
select *
from student_homework;
4.开始做题
select id,class,name from student;
select *
from student_course;
select class from student;
select course_id,course_name from student_course where student_time>60;
select id,name,date from student where date>=('1986-1-1') AND date<('1987-1-1');
select id,name,class from student where name like '张%';
select * from student where class like '%05' and gender='男';
select id,course_id from student_homework where homework_1 is null or homework_2 is null or homework_3 is null ;
select sum(homework_1) '总分' from student_homework where id='0538';
select count(*) from student_homework where course_id='K001';
select count(*) from student where class is not null ;
select student.id, avg(homework_1), avg(homework_2), avg(homework_3)
from student
left join student_homework on student.id = student_homework.id
group by student.id
having count(course_id) >= 3;