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android 再按一次后退键退出应用程序


private static Boolean isExit = false;  
private static Boolean hasTask = false;
Timer tExit = new Timer();
TimerTask task = new TimerTask() {

@Override
public void run() {
isExit = false;
hasTask = true;
}
};

@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
System.out.println("TabHost_Index.java onKeyDown");
if (keyCode == KeyEvent.KEYCODE_BACK) {
if(isExit == false ) {
isExit = true;
Toast.makeText(this, "再按一次后退键退出应用程序", Toast.LENGTH_SHORT).show();
if(!hasTask) {
tExit.schedule(task, 2000);
}
} else {
finish();
System.exit(0);
}
}
return false;
}

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