Given a positive integer n, generate a square matrix filled with elements from 1 to n2 in spiral order.
Example:
Input: 3
Output:
[
[ 1, 2, 3 ],
[ 8, 9, 4 ],
[ 7, 6, 5 ]
]
题解:
class Solution {
public:
void getSpiralOrder(int n, int k, vector<vector<int>> &res, int l, int r, int u, int d) {
if (l == r && u == d) {
res[u][l] = k++;
}
else {
for (int i = l; i < r; i++) {
res[u][i] = k++;
}
for (int i = u; i < d; i++) {
res[i][r] = k++;
}
for (int i = r; i > l; i--) {
res[d][i] = k++;
}
for (int i = d; i > u; i--) {
res[i][l] = k++;
}
}
if (k > n) {
return;
}
getSpiralOrder(n, k, res, l + 1, r - 1, u + 1, d - 1);
}
vector<vector<int>> generateMatrix(int n) {
if (n == 0) {
return {};
}
if (n == 1) {
return {{1}};
}
vector<vector<int>> res(n, vector<int>(n, 0));
getSpiralOrder(n * n, 1, res, 0, n - 1, 0, n - 1);
return res;
}
};