Maven打可执行jar包

1. 需求

maven默认package打包, 只包含项目代码, 没有引入项目代码依赖的lib包, 执行时缺包

那么如何将依赖的lib文件打进jar包呢?

2. Assembly插件

assembly插件用于maven工程打包, 将项目代码与依赖lib包打进一个jar文件中

2.1. 配置

<artifactId>maven-assembly-plugin</artifactId>引入assembly插件
<executions>打包命令绑定到mvn package阶段
<descriptorRef>使用内置的jar-with-dependencies描述性文件 (内置的还有bin, src, project, 这里不作讨论), 工具提供的通用打jar包手段
<manifest>可执行jar包需要在MANIFEST.MF文件中指定Main-Class属性

<plugin>
	<groupId>org.apache.maven.plugins</groupId>
	<artifactId>maven-assembly-plugin</artifactId>
	<version>2.4</version>
	<executions>
		<execution>
			<phase>package</phase>
			<goals>
				<goal>single</goal>
			</goals>
		</execution>
	</executions>
	<configuration>
		<descriptorRefs>
			<descriptorRef>jar-with-dependencies</descriptorRef>
		</descriptorRefs>
		<archive>
			<manifest>
				<mainClass>xxx.yyy.zzz</mainClass>
			</manifest>
		</archive>
	</configuration>
</plugin>

2.2. jar-with-dependencies

描述如何打包, 将依赖的lib包拆包后再与项目代码打进jar包

<assembly xmlns="http://maven.apache.org/ASSEMBLY/2.1.0"
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="http://maven.apache.org/ASSEMBLY/2.1.0 http://maven.apache.org/xsd/assembly-2.1.0.xsd">
  <!-- TODO: a jarjar format would be better -->
  <id>jar-with-dependencies</id>
  <formats>
    <format>jar</format>
  </formats>
  <includeBaseDirectory>false</includeBaseDirectory>
  <dependencySets>
    <dependencySet>
      <outputDirectory>/</outputDirectory>
      <useProjectArtifact>true</useProjectArtifact>
      <unpack>true</unpack>
      <scope>runtime</scope>
    </dependencySet>
  </dependencySets>
</assembly>

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