题目：原题链接（简单）
标签：字符串
解法 | 时间复杂度 | 空间复杂度 | 执行用时 |
Ans 1 (Python) | 36ms (87.10%) | ||
Ans 2 (Python) | |||
Ans 3 (Python) |
解法一：
def toGoatLatin(self, S: str) -> str:
S = S.split(" ")
ans = []
for i in range(len(S)):
s = S[i]
if s[0] not in ["A", "E", "I", "O", "U", "a", "e", "i", "o", "u"]:
s = s[1:] + s[0]
s += "m" + "a" * (i + 2)
ans.append(s)
return " ".join(ans)
