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古罗马--模板


计算古罗马加法,输入不合法,则输出“Aha! I don't need to calculate the sum”。

 







测试用例 1

以文本方式显示



  1. I↵
  2. I↵


以文本方式显示



  1. II↵


1秒

64M

0


#include<stdio.h>
#include<string.h>
#include<stdlib.h>


char p[5][11][10];
void dabiao()
{
	memset(p,0,sizeof(p));
	strcpy(p[1][1],"I");
	strcpy(p[1][2],"II");
	strcpy(p[1][3],"III");
	strcpy(p[1][4],"IV");
	strcpy(p[1][5],"V");
	strcpy(p[1][6],"VI");
	strcpy(p[1][7],"VII");
	strcpy(p[1][8],"VIII");
	strcpy(p[1][9],"IX");
	strcpy(p[2][1],"X");
	strcpy(p[2][2],"XX");
	strcpy(p[2][3],"XXX");
	strcpy(p[2][4],"XL");
	strcpy(p[2][5],"L");
	strcpy(p[2][6],"LX");
	strcpy(p[2][7],"LXX");
	strcpy(p[2][8],"LXXX");
	strcpy(p[2][9],"XC");
	strcpy(p[3][1],"C");
	strcpy(p[3][2],"CC");
	strcpy(p[3][3],"CCC");
	strcpy(p[3][4],"CD");
	strcpy(p[3][5],"D");
	strcpy(p[3][6],"DC");
	strcpy(p[3][7],"DCC");
	strcpy(p[3][8],"DCCC");
	strcpy(p[3][9],"CM");
	strcpy(p[4][1],"M");
	strcpy(p[4][2],"MM");
}

char a[20],b[20];
int aa[20],bb[20];
int main()
{
	dabiao();
	scanf("%s",a);
	scanf("%s",b);
	int la=strlen(a);
	int lb=strlen(b);
	int za=0,zb=0;
	int i,j,k;
	int I=1,V=5,X=10,L=50,C=100,D=500,M=1000;
	memset(aa,0,sizeof(aa));
	memset(bb,0,sizeof(bb));
	for(i=0;i<la;i++)
	{
		if(a[i]=='I')
			aa[i]=I;
		else if(a[i]=='V')
			aa[i]=V;
		else if(a[i]=='X')
			aa[i]=X;
		else if(a[i]=='L')
			aa[i]=L;
		else if(a[i]=='C')
			aa[i]=C;
		else if(a[i]=='D')
			aa[i]=D;
		else if(a[i]=='M')
			aa[i]=M;
	}
	for(i=0;i<lb;i++)
	{
		if(b[i]=='I')
			bb[i]=I;
		else if(b[i]=='V')
			bb[i]=V;
		else if(b[i]=='X')
			bb[i]=X;
		else if(b[i]=='L')
			bb[i]=L;
		else if(b[i]=='C')
			bb[i]=C;
		else if(b[i]=='D')
			bb[i]=D;
		else if(b[i]=='M')
			bb[i]=M;
	}
	for(i=0;i<la;i++)
	{
		if(aa[i]>=aa[i+1])
			za+=aa[i];
		else{
			za+=aa[i+1]-aa[i];
			i++;
		}
	}
	for(i=0;i<lb;i++)
	{
		if(bb[i]>=bb[i+1])
			zb+=bb[i];
		else{
			zb+=bb[i+1]-bb[i];
			i++;
		}
	}

	int flag=0;
	char ta[20];
	char tb[20];
	memset(ta,0,sizeof(ta));
	memset(tb,0,sizeof(tb));
	int temp=za/1000;
	if(temp!=0)
		strcat(ta,p[4][temp]);
	temp=(za/100)%10;
	if(temp!=0)
		strcat(ta,p[3][temp]);
	temp=(za/10)%10;
	if(temp!=0)
		strcat(ta,p[2][temp]);
	temp=za%10;
	if(temp!=0)
		strcat(ta,p[1][temp]);
	if(strcmp(a,ta)!=0)
		flag=1;

	temp=zb/1000;
	if(temp!=0)
		strcat(tb,p[4][temp]);
	temp=(zb/100)%10;
	if(temp!=0)
		strcat(tb,p[3][temp]);
	temp=(zb/10)%10;
	if(temp!=0)
		strcat(tb,p[2][temp]);
	temp=zb%10;
	if(temp!=0)
		strcat(tb,p[1][temp]);
	if(strcmp(b,tb)!=0)
		flag=1;
	
	if(flag==0){
	
	int sum=za+zb;
	int temp=sum/1000;
	if(temp!=0)
		printf("%s",p[4][temp]);
	temp=(sum/100)%10;
	if(temp!=0)
		printf("%s",p[3][temp]);
	temp=(sum/10)%10;
	if(temp!=0)
		printf("%s",p[2][temp]);
	temp=sum%10;
	if(temp!=0)
		printf("%s",p[1][temp]);
	printf("\n");
	}
	else
		printf("Aha! I don't need to calculate the sum\n");
	system("pause");
}




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