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一个联系人下多个号码去重复

您好 2022-08-04 阅读 22


public class Test {

public static void main(String[] args) {
Map<String ,List<String>> map = new HashMap<String ,List<String>>();
Set<String> nameSet = new HashSet<String>();
List<Contract> list = getContracts();
for(Contract c : list){
nameSet.add(c.getName());
}
for(String name : nameSet){
List<String> phones = new ArrayList<String>();
for(Contract c : list){
if(name.equals(c.getName())){
phones.add(c.getPhone());
}
}
map.put(name, phones);
}
System.out.println(map);
}

public static List<Contract> getContracts(){
String[] name = {"Tom","Jack","Mike","Tony"};
List<Contract> list = new ArrayList<Contract>();
list.add(new Contract(101,name[0],"11111111"));
list.add(new Contract(102,name[0],"22222222"));
list.add(new Contract(103,name[1],"33333333"));
list.add(new Contract(104,name[1],"44444444"));
list.add(new Contract(105,name[2],"55555555"));
list.add(new Contract(106,name[2],"66666666"));
list.add(new Contract(107,name[3],"77777777"));
list.add(new Contract(108,name[3],"88888888"));
return list;
}
}

 

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