前言：

1.一维数组：

int main()
{
	int a[] = { 1,2,3,4 };
	printf("%d\n", sizeof(a));
	printf("%d\n", sizeof(a + 0));
	printf("%d\n", sizeof(*a));
	printf("%d\n", sizeof(a + 1));
	printf("%d\n", sizeof(a[1]));
	printf("%d\n", sizeof(&a));
	printf("%d\n", sizeof(*&a));
	printf("%d\n", sizeof(&a + 1));
	printf("%d\n", sizeof(&a[0]));
	printf("%d\n", sizeof(&a[0] + 1));

    return 0;
}

运行结果：

🎈解析：

printf("%d\n",sizeof(a));

printf("%d\n",sizeof(a[0][0]));

printf("%d\n", sizeof(*a));

printf("%d\n", sizeof(a + 1));

printf("%d\n", sizeof(a[1]));

printf("%d\n", sizeof(&a));

printf("%d\n", sizeof(*&a));

printf("%d\n", sizeof(&a + 1));

printf("%d\n", sizeof(&a[0]));

printf("%d\n", sizeof(&a[0] + 1));

2.字符数组：

2.1题型一：

int main()
{
	char arr[] = { 'a','b','c','d','e','f' };
	
	printf("%d\n", sizeof(arr));
    printf("%d\n", sizeof(arr+0));
    printf("%d\n", sizeof(*arr));
    printf("%d\n", sizeof(arr[1]));
    printf("%d\n", sizeof(&arr));
    printf("%d\n", sizeof(&arr+1));
    printf("%d\n", sizeof(&arr[0]+1));

	return 0;
}

运行结果：

🎈解析：

printf("%d\n", sizeof(arr));

printf("%d\n", sizeof(arr+0));

printf("%d\n", sizeof(*arr));

printf("%d\n", sizeof(arr[1]));

printf("%d\n", sizeof(&arr));

printf("%d\n", sizeof(&arr+1));

printf("%d\n", sizeof(&arr[0]+1));

🎈下面我们将这个代码稍微变动一下，将sizeof变为strlen，我们再来分析一下 :

#include <string.h>
int main()
{
	char arr[] = { 'a','b','c','d','e','f' };//末尾没有\0

	printf("%d\n", strlen(arr));
	printf("%d\n", strlen(arr + 0));
	//printf("%d\n", strlen(*arr));//err
	//printf("%d\n", strlen(arr[1]));//err
	printf("%d\n", strlen(&arr));
	printf("%d\n", strlen(&arr + 1));
	printf("%d\n", strlen(&arr[0] + 1));

	return 0;
}

运行结果：

🎈解析：

printf("%d\n", strlen(arr));

printf("%d\n", strlen(arr+0));

printf("%d\n", strlen(*arr));

printf("%d\n", strlen(arr[1]));

printf("%d\n", strlen(&arr));

printf("%d\n", strlen(&arr+1));

printf("%d\n", strlen(&arr[0]+1));

2.2题型二：

int main()
{
    char arr[] = "abcdef";//a b c d e f \0

    printf("%d\n", sizeof(arr));
    printf("%d\n", sizeof(arr + 0));
    printf("%d\n", sizeof(*arr));
    printf("%d\n", sizeof(arr[1]));
    printf("%d\n", sizeof(&arr));
    printf("%d\n", sizeof(&arr + 1));
    printf("%d\n", sizeof(&arr[0] + 1));

    return 0;
}

运行结果：

🎈解析：

printf("%d\n", sizeof(arr));

printf("%d\n", sizeof(arr+0));

printf("%d\n", sizeof(*arr));

printf("%d\n", sizeof(arr[1]));

printf("%d\n", sizeof(&arr));

printf("%d\n", sizeof(&arr+1));

printf("%d\n", sizeof(&arr[0]+1));

🎈下面我们再来将这个代码变动一下，将sizeof变为strlen

#include <string.h>

int main()
{
	char arr[] = "abcdef";
	printf("%d\n", strlen(arr));
	printf("%d\n", strlen(arr + 0));
	//printf("%d\n", strlen(*arr));//err
	//printf("%d\n", strlen(arr[1]));///err
	printf("%d\n", strlen(&arr));
	printf("%d\n", strlen(&arr + 1));
	printf("%d\n", strlen(&arr[0] + 1));
	return 0;
}

运行结果：

🎈解析：

printf("%d\n", strlen(arr));

printf("%d\n", strlen(arr+0));

printf("%d\n", strlen(*arr));

printf("%d\n", strlen(arr[1]));

printf("%d\n", strlen(&arr));

printf("%d\n", strlen(&arr+1));

printf("%d\n", strlen(&arr[0]+1));

2.3题型三：

int main()
{
    //把字符串首字符的地址放到了p里边去，也就是说p指向了"abcdef"
	char* p = "abcdef";

	printf("%d\n", sizeof(p));
	printf("%d\n", sizeof(p + 1));
	printf("%d\n", sizeof(*p));
	printf("%d\n", sizeof(p[0]));
	printf("%d\n", sizeof(&p));
	printf("%d\n", sizeof(&p + 1));
	printf("%d\n", sizeof(&p[0] + 1));
	return 0;
}

运行结果：

🎈解析：

printf("%d\n", sizeof(p));

printf("%d\n", sizeof(p+1));

printf("%d\n", sizeof(*p));

printf("%d\n", sizeof(p[0]));

printf("%d\n", sizeof(&p));

printf("%d\n", sizeof(&p+1));

printf("%d\n", sizeof(&p[0]+1));

🎈 将sizeof变为strlen，我们继续分析：

int main()
{
	char* p = "abcdef";//a b c d e f \0

	printf("%d\n", strlen(p));
	printf("%d\n", strlen(p + 1));
	printf("%d\n", strlen(*p));
	printf("%d\n", strlen(p[0]));
	printf("%d\n", strlen(&p));
	printf("%d\n", strlen(&p + 1));
	printf("%d\n", strlen(&p[0] + 1));
	return 0;
}

🎈解析：