HDU 2054 A == B ? 字符串处理

A == B ?

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 63662    Accepted Submission(s): 9961

Problem Description

Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".

Input

each test case contains two numbers A and B.

Output

for each case, if A is equal to B, you should print "YES", or print "NO".

Sample Input

1 2 2 2 3 3 4 3

Sample Output

NO YES YES NO

/*
HDU 2054 字符串处理 
刚开始没看懂 看了下别人的 这题不好 啥都没说明
有人说有+ -号 但是好像没有 
去除前置的的0和小数点后不为零数字后面的0

0000.1   0.1000000
.1     0.1
000.000     0
123456789123456789 123456789123456789
000001000.  1000
*/
#include<iostream>
#include<stdio.h>
#include<string>
using namespace std;
void change(string &str)
{
    if(strchr(str.c_str(), '.' ) )  
    {  
        int last=str.length();  
        while(str[--last]=='0') 
            str.erase(last,1); //删除后置0  
        if(str[last]=='.')
            str.erase(last,1) ; //若全为0，删除小数点  
    }  
    while(str[0]=='0')//前置0的处理  
    {  
        if(str.length()!=1) 
            str.erase(0,1);//若全为0，则保存一个0  
        else return;  
    }  
}
int  main()
{
    string num1,num2;
    while(cin>>num1>>num2)
    {
        change(num1);
        change(num2);
        if(num1.compare(num2)==0) 
            cout<<"YES"<<endl;  
        else 
            cout<<"NO"<<endl;  
        
    }
    return 0;
}