题目:原题链接(困难)
标签:SQL
解法 | 时间复杂度 | 空间复杂度 | 执行用时 |
Ans 1 (Python) | 399ms (46.46%) | ||
Ans 2 (Python) | |||
Ans 3 (Python) |
解法一:
SELECT student_id,
student_name
FROM Student
WHERE student_id NOT IN (SELECT DISTINCT student_id
FROM Exam AS E1
LEFT JOIN
(SELECT exam_id,
MIN(score) AS min_score,
MAX(score) AS max_score
FROM Exam
GROUP BY exam_id) AS E2 ON E2.exam_id = E1.exam_id
WHERE E1.score = E2.min_score
OR E1.score = E2.max_score)
AND student_id IN (SELECT DISTINCT student_id FROM Exam);