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<leetcode>226.翻转二叉树——树

给你一棵二叉树的根节点 root ,翻转这棵二叉树,并返回其根节点。

解答:递归

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
public:
    void helper(TreeNode* &root){
        if(root == nullptr) return;
        TreeNode* tmp;
        tmp = root->left;
        root->left = root->right;
        root->right = tmp;
        helper(root->left);
        helper(root->right);
        
    }

    TreeNode* invertTree(TreeNode* root) {
        if(root == nullptr) return root;
        helper(root);
        return root;
    }
};
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