0
点赞
收藏
分享

微信扫一扫

AcWing 1191. 家谱树

棒锤_45f2 2022-03-30 阅读 60


​​题目传送门​​

拓扑排序祼题模板

#include <bits/stdc++.h>
using namespace std;

const int N = 110, M = N * N;

int n;
int q[N];
int d[N];
int h[N], e[M], ne[M], idx;
void add(int a, int b) {
e[idx] = b, ne[idx] = h[a], h[a] = idx++;
}

void topsort() {
int hh = 0, tt = -1;
//所有入度为0的入队列
for (int i = 1; i <= n; i++)
if (!d[i])
q[++tt] = i;

while (hh <= tt) {
int t = q[hh++];
for (int i = h[t]; ~i; i = ne[i]) {
int j = e[i];
if (--d[j] == 0)
q[++tt] = j;
}
}
}

int main() {
memset(h, -1, sizeof h);
cin >> n;
for (int i = 1; i <= n; i++) {
int son;
while (cin >> son, son) {
add(i, son);
d[son]++; //入度++
}
}
//拓扑序
topsort();
//输出任意一组拓扑序,q数组中就记录的拓扑序
for (int i = 0; i < n; i++) printf("%d ", q[i]);
return 0;
}



举报

相关推荐

0 条评论