1.利用RadASM 写汇编程序
本文介绍利用RedASM写一个messageBox “hello world”.
.386
.model flat, stdcall
option casemap :none
include windows.inc
include kernel32.inc
include masm32.inc
includelib kernel32.lib
includelib masm32.lib
.data
helloWorld db "hello world",0
.code
start:
invoke StdOut, addr helloWorld
invoke ExitProcess,0
end start
2.习题：有1、2、3、4个数字，能组成多少个互不相同且无重复数字的三位数？都是多少？
写成c代码很简单：
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void p1_fun()
{
for (int i = 1; i <= 4; ++i){
for (int j = 1; j <= 4; ++j){
for (int k = 1; k <=4; ++k){
if (i !=j && i !=k && j != k){
ostringstream stringStream;
stringStream<<i<<j<<k;
cout<<stringStream.str()<<",";
}
}
}
}
}
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用汇编实现如下
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Title: Hello world
;Author: sld6666666@gmail.com
;Data: 2012-11-29
;Description: Assemble hello world
.386 ;¸Ã³ÌÐò¶ÔCPUµÄ×îµÍÒªÇóÊÇintel 386
.model flat, stdcall ; ƽ̹ÄÚ´æÄ£ÐÍ£¬ stacll º¯Êýµ÷Ó÷½Ê½
.stack 4096 ;Õ»µÄ´óСΪ4096B
option casemap:none
;include Í·Îļþ£¬ Á¬½Ó¿â
include msvcrt.inc
includelib msvcrt.lib
.data ;Êý¾Ý¶Î
index_0 dd dword
index_1 dd dword
index_2 dd dword
szFmt db '%d%d%d', 0
entryFmt db ' ',0
.code
start:
mov index_0, 0
forProcess_0:
cmp index_0, 5
jge rtnProcess
inc index_0
mov index_1, 0
forProcess_1:
cmp index_1, 5
jge forProcess_0
inc index_1
mov index_2, 0
forProcess_2:
cmp index_2, 5
jge forProcess_1
inc index_2
mov eax, index_0
mov ebx, index_1
mov edx, index_2
cmp eax, ebx
je forProcess_2
cmp eax, edx
je forProcess_2
cmp ebx, edx
je forProcess_2
invoke crt_printf, addr szFmt,eax, ebx, edx
invoke crt_printf, addr entryFmt
jmp forProcess_2
rtnProcess:
ret
end start
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