题目链接：点击打开链接
题目大意：略。
解题思路：略。
AC 代码
-- 解决方案(1)
select p.project_id, p.employee_id
from Project p
join Employee e
on p.employee_id = e.employee_id
where (p.project_id, e.experience_years) in (
select p.project_id,max(e.experience_years)
from project p join employee e on p.employee_id = e.employee_id
group by p.project_id)
-- 解决方案(2)
SELECT project_id, employee_id
FROM (SELECT project_id, e.employee_id, RANK() OVER(PARTITION BY project_id ORDER BY experience_years DESC) rnk
FROM Employee e JOIN Project p ON e.employee_id = p.employee_id) RS
WHERE rnk = 1
