0
点赞
收藏
分享

微信扫一扫

基础的js事件

12a597c01003 2022-04-23 阅读 56
javascript

<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>js事件</title>

<script type="text/javascript">

window.onload = function(){
    document.getElementById("ceshi").onclick = function(){
        console.log("事件注册一个方法,完美解释案件");
    }

    document.getElementById("div1").onmousedown = function(){
        console.log("鼠标按下");
    }
    document.getElementById("div1").onmouseover = function(){
        console.log("鼠标经过");
    }
    document.getElementById("div1").onmousemove = function(){
        console.log("鼠标移动");
    }
    document.getElementById("div1").onmouseout = function(){
        console.log("鼠标离开");
    }
    document.getElementById("div1").onmouseup = function(){
        console.log("鼠标弹起");
    }
}

</script>

<style>
#div1{
    height:500px;
    width:500px;
    border:3px solid yellow;
    background: red
}
</style>

</head>
<body οnlοad="console.log('页面加载完毕')">

<input type="button" id="ceshi" value="按钮"><br><br>

<input type="text" οnblur="console.log('失去光标')" οnfοcus="console.log('聚焦光标')"><br><br>
<input type="button" value="按钮" οnclick="console.log('单击事件')" οndblclick="console.log('双击鼠标')"><br><br>
<input type="text" οnkeydοwn="console.log('键盘按下')" οnkeyup="console.log('键盘弹起')"><br><br>

<form  οnsubmit="alert('表单提交了')" οnreset="console.log('表单重置')">
<input type="submit" value="提交">
<input type="reset" value="重置">
</form>
<br><br>
<textarea οnselect="console.log('文本选中')"> </textarea>
<input type="text" οnselect="console.log('文本选中')">
<br><br>
<select οnchange="console.log('下拉列表改变了')">
    <option>1</option>
    <option>2</option>
    <option>3</option>
    <option>4</option>
</select>

<br><br>
<br><br>

<div id="div1"></div>

</body>
<script type="text/javascript">
    alert('测试页面加载');
</script>
</html>

举报

相关推荐

0 条评论