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LeetCode-797. All Paths From Source to Target

芭芭蘑菇 2022-08-10 阅读 84


Given a directed, acyclic graph of ​​N​​​ nodes.  Find all possible paths from node ​​0​​​ to node ​​N-1​​, and return them in any order.

The graph is given as follows:  the nodes are 0, 1, ..., graph.length - 1.  graph[i] is a list of all nodes j for which the edge (i, j) exists.

Example:
Input: [[1,2], [3], [3], []]
Output: [[0,1,3],[0,2,3]]
Explanation: The graph looks like this:
0--->1
| |
v v
2--->3
There are two paths: 0 -> 1 -> 3 and 0 -> 2 -> 3.

Note:

  • The number of nodes in the graph will be in the range​​[2, 15]​​.
  • You can print different paths in any order, but you should keep the order of nodes inside one path.

题解:

class Solution {
public:
void dfs(vector<vector<int>>& graph, int k, int n, vector<int> &cur, vector<vector<int>> &res) {
if (k == n) {
res.push_back(cur);
}
else {
for (int i = 0; i < graph[k].size(); i++) {
cur.push_back(graph[k][i]);
dfs(graph, graph[k][i], n, cur, res);
cur.pop_back();
}
}
}
vector<vector<int>> allPathsSourceTarget(vector<vector<int>>& graph) {
int n = graph.size();
vector<vector<int>> res;
vector<int> cur(1, 0);
dfs(graph, 0, n - 1, cur, res);
return res;
}
};

 

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