0
点赞
收藏
分享

微信扫一扫

1572. 矩阵对角线元素的和

闲云困兽 2022-07-28 阅读 55


1572. 矩阵对角线元素的和_i++

class Solution {
public int diagonalSum(int[][] mat) {
int sum = 0, len = mat[0].length;
for (int i = 0; i < len; i++){
sum += mat[i][i];
}
for (int i = 0; i < len; i++){
for (int j = 0; j < len; j++){
if (i + j == len - 1)
sum += mat[i][j];
}
}
return len%2 == 1 ? sum - mat[(len - 1)/2][(len - 1)/2] : sum;
}
}

1572. 矩阵对角线元素的和_i++_02


举报

相关推荐

0 条评论