1083 List Grades (25 分)-CFANZ编程社区

1083 List Grades (25 分)

Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:

Each input file contains one test case. Each case is given in the following format:

N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
... ...
name[N] ID[N] grade[N]
grade1 grade2

where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade's interval. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student's name and ID, separated by one space. If there is no student's grade in that interval, output NONE instead.

Sample Input 1:

4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100

Sample Output 1:

Mike CS991301
Mary EE990830
Joe Math990112

Sample Input 2:

2
Jean AA980920 60
Ann CS01 80
90 95

Sample Output 2:

NONE

又变得很简单的一个排序题，但是千万不要轻敌。。莫名其妙的错误浪费时间

#include<bits/stdc++.h>
using namespace std;

struct student{
  string name,id;
  int grade;
}stu[10000];

bool compare(student a,student b){
  return a.grade>b.grade;
}

int main(){
  //freopen("in.txt","r",stdin);
  int N,a,b;
  cin>>N;
  for(int i=0;i<N;i++){
    cin>>stu[i].name>>stu[i].id>>stu[i].grade;
  }
  cin>>a>>b;
  sort(stu,stu+N,compare);
  bool out=false;
  for(int i=0;i<N;i++){
    if(stu[i].grade<a) break;//<abreak    不是>b break   脑子迟钝了。。。记录是按学生成绩降序排的呀 
    if(stu[i].grade>=a&&stu[i].grade<=b){
      out=true;
      cout<<stu[i].name<<" "<<stu[i].id<<endl;
    } 
  }
  if(!out) cout<<"NONE"; 
  return 0;
}