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QT readyRead()函数,数据分包不完整解决办法

柠檬的那个酸_2333 2024-09-09 阅读 6

目录

一、vector的基本实现机制:

二、vector的部分接口模拟实现:

1、构造与析构:

1、普通构造:

2、拷贝构造:

3、析构函数:

2、关于扩容:

1、reserve:

2、resize

3、增删查改:

1、在pos位置插入:

2、[]符号访问修改:

3、删除pos位置的值:

4、重载=运算符:


一、vector的基本实现机制:

namespace ppr
{
	template<class T>
	class vector
	{
	public:
		typedef T* iterator;
		typedef const T* const_iterator;
		
		iterator begin() 
		{
			return _start;
		}

		iterator end()
		{
			return _finish;
		}

		const_iterator begin() const
		{
			return _start;
		}

		const_iterator end() const
		{
			return _finish;
		}

        size_t size() const
        {
        	return _finish - _start;
        }

        size_t capacity() const
        {
	        return _endofstorage - _start;
        }
	private:
		iterator _start;
		iterator _finish;
		iterator _endofstorage;
	};

二、vector的部分接口模拟实现:

1、构造与析构:

1、普通构造:

vector()
	:_start(nullptr)
	, _finish(nullptr)
	, _endofstorage(nullptr)
{}

2、拷贝构造:

vector(const vector<T>& v)
	:_start(nullptr)
	, _finish(nullptr)
	, _endofstorage(nullptr)
{
	_start = new T[v.capacity()];
	memcpy(_start, v._start.sizeof(T) * v.size());
	_finish = _start + v.size();
	_endofstorage = _start + v.capacity();
}

3、析构函数:

~vector()
{
	if (_start != nullptr)
	{
		delete[] _start;
		_start = _finish = _endofstorage = nullptr;
	}
}

2、关于扩容:

1、reserve:

void reserve(size_t n)
{
	size_t sz = size();
	if (n > capacity())
	{
		T* tmp = new T[n];
		if (_start != nullptr)
		{
			memcpy(tmp, _start, sizeof(T) * sz);
			delete[] _start;
		}
		_start = tmp;
		_finish = _start + sz;
		_endofstorage = _start + n;
	}
}

2、resize

void resize(size_t n,const T& val = T())
{
	if (n < size())
	{
		_finish = _start + n;
	}
	else
	{
		reserve(n);

		while (_finish != _start + n)
		{
			*_finish = val;
			_finish++;
		}
	}
}

3、增删查改:

1、在pos位置插入:

iterator insert(iterator pos ,const T& x)
{
	assert(pos >= _start && pos <= _finish);

	if (_finish == _endofstorage)
	{
		size_t len = pos - _start;

		size_t newcapacity = capacity() == 0 ? 4 : capacity() * 2; 
		reserve(newcapacity); 

		pos = _start + len;
	}

	iterator end = _finish - 1;
	while (end >= pos)
	{
		*(end + 1) = *end;
		--end;
	}

	*pos = x;
	_finish++; 

	return pos;
}

2、[]符号访问修改:

T& operator[](size_t pos)
{
	assert(pos<size());

	return _start[pos];
}

const T& operator[](size_t pos) const 
{
	assert(pos < size());

	return _start[pos];
}

3、删除pos位置的值:

iterator erase(iterator pos)
{
	assert(pos >= _start && pos < _finish);

	iterator it = pos + 1;
	while (it != _finish)
	{
		*(it - 1) = *it;
		++it;
	}
	--_finish;
	return pos;
}

4、重载=运算符:

void swap(vector<T>& v)
{
	std::swap(_start, v._start); 
	std::swap(_finish, v._finish); 
	std::swap(_endofstorage, v._endofstorage); 
}

vector<T>& operator=(vector<T> v)
{
	swap(v);
	return *this;
}
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