N!
Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others)
Total Submission(s): 65655 Accepted Submission(s): 18807
Problem Description
Given an integer N(0 ≤ N ≤ 10000), your task is to calculate N!
Input
One N in one line, process to the end of file.
Output
For each N, output N! in one line.
Sample Input
1
2
3
Sample Output
1
2
6
Author
JGShining(极光炫影)
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第一次 想这数组开小点1w把。。其实真不小了。。
可我还是太嫩了。。原来要开到35700。。
#include <stdio.h>
#include <string.h>
using namespace std;
#define N 35700
int main()
{
int n;
char num[N];
while(scanf("%d",&n)!=EOF)
{
memset(num,'0',sizeof(num));
num[0]='1';
for(int i=2;i<=n;i++)
{
int r=0,k;
for(int j=0;j<N;j++)
{
k=(num[j]-'0')*i+r;
num[j]=k%10+'0';
r=k/10;
}
}
int i;
for(i=N-1;i>=0;i--)
if(num[i]!='0')
break;
for(int j=i;j>=0;j--)
printf("%c",num[j]);
printf("\n");
}
return 0;
}