continue:对1到100之间的奇数进行求和
#include <stdio.h>
int main()
{
int i, total;
for (i = 1, total = 0; i <= 100; i++)
{
if (i % 2 == 0)
{
continue;//提前结束i为偶数的这轮循环
}
total = total + i;
}
printf("total=%d\n", total);
}
break
#include <stdio.h>
int main()
{
int i, total;
for (i = 1, total = 0; i <= 100; i++)
{
if (total > 2000)
{
break;//当求和大于2000,就中止循环
}
total = total + i;
}
printf("total=%d,i=%d\n", total, i);
return 0;
}