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Oracle授权A用户查询B用户的所有表

西曲风 2022-04-06 阅读 212
sqloracleide


1.1 grant select any table

SQL> conn / as sysdba;

SQL> grant select any table on userA;

这种方法的缺点是授予的权限过大,userA不仅可以访问scott下的所有表,也可以访问其他用户包括sys,system下的所有表。

1.2 逐个授权

SQL> conn scott/tiger;

SQL> select 'GRANT SELECT ON '||table_name||' to query01;'  from user_tables;

再把上面得到的结果逐一执行一遍:

这种方法的缺点是要执行比较多的语句,如果有100个表,就得执行100个grant语句;

另外scott新建的表不在被授权的范围内,新建的表要想被userA访问,也得执行grant语句:

grant select on 新建的表 to userA;

1.3 使用游标

先创建两个用户

SQL> create user test1 identified by oracle;

User created.

SQL> create user test2 identified by oracle;

User created

授权

SQL> grant connect, resource to test1;

Grant succeeded.


SQL> grant connect, resource to test2;

Grant succeeded.


在test2下建立一个表作测试用

SQL> conn test2/oracle;

Connected.


SQL> create table t(id number);

Table created.


创建角色并用游标给角色授权

SQL> conn /as sysdba;

Connected.


SQL> create role select_all_test2_tab;

Role created


SQL> 

declare

  CURSOR c_tabname is select table_name from dba_tables where owner = 'TEST2';

  v_tabname dba_tables.table_name%TYPE;

  sqlstr    VARCHAR2(200);


begin

  open c_tabname;

  loop

    fetch c_tabname into v_tabname;

    exit when c_tabname%NOTFOUND;

    sqlstr := 'grant select on test2.' || v_tabname ||' to select_all_test2_tab';

    execute immediate sqlstr;

  end loop;

  close c_tabname;

end;

/


PL/SQL procedure successfully completed.


把角色授权给test1

SQL> grant select_all_test2_tab to test1;

Grant succeeded.


尝试用test1访问test2的表

SQL> conn test1/oracle;

Connected.


SQL> select * from test2.t;

no rows selected


在test2下新建表

SQL> conn test2/oracle;

Connected.

SQL> create table ta(id number);

Table created.


尝试用test1访问新建的表

SQL> conn test1/oracle;

Connected.

SQL> select * from test2.ta;

select * from test2.ta

                    *

ERROR at line 1:

ORA-00942: table or view does not exist

结论:与第二种方案相比,用这种方式不需逐一把test2下的表授权给test1访问,但test2新建的表无法被test1访问。


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