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Java学习-Day4

有点d伤 2022-04-13 阅读 74
eclipse

day4
总结:
1、闰年的判断逻辑本身很简单 %4==0&&%100!=0。
2、boolean类型只有两个值:true、false。

package day4;

public class text1 {

public static void main(String args[])
{
	int year =2022;
	System.out.print("" + year + " is ");
	
	if(!isleapyear(year))
	{
	   System.out.println("NOT .");
	}
	else
	{
		System.out.println("a leap year.");
	}
	
	year=2000;
	System.out.print("" + year + " is ");
	if(!isleapyear(year))
	{
	   System.out.print("NOT .");
	}
	else
	{
		System.out.println("a leap year.");
	}
	
	year=2004;
	System.out.print("" + year + " is ");
	if(!isleapyear(year))
	{
	   System.out.print("NOT .");
	}
	else
	{
		System.out.println("a leap year.");
	}
	
	year=2021;
	System.out.print("" + year + " is ");
	if(!isleapyear(year))
	{
	   System.out.println("NOT .");
	}
	else
	{
		System.out.println("a leap year.");
	}
	
	year=2008;
	System.out.print("" + year + " is ");
	if(!isleapyear(year))
	{
	   System.out.println("NOT .");
	}
	else
	{
		System.out.println("a leap year.");
	}
	
}

public static boolean isleapyear(int year) {
	if ((year % 4 == 0) && (year % 100 != 0) || (year % 400 == 0)) {
		return true;
	} else {
		return false;
	} // Of if
}

}

结果:
在这里插入图片描述

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