0
点赞
收藏
分享

微信扫一扫

Linux占用内存脚本


/*usage: cc mem.c -o mem.out 后 使用./mem.out 100 & 消耗对应数字MB单位的内存,释放时杀掉对应进程即可*/
#include <stdlib.h>
#include <stdio.h>
#include <unistd.h>

#define UNIT (1024*1024)

int main(int argc, char *argv[])
{
long long i = 0;
int size = 0;

if (argc != 2) {
printf(" === argc must 2\n");
return 1;
}
size = strtoull(argv[1], NULL, 10);
if (size == 0) {
printf(" argv[1]=%s not good\n", argv[1]);
return 1;
}

char *buff = (char *) malloc(size * UNIT);
if (buff)
printf(" we malloced %d Mb\n", size);
buff[0] = 1;

for (i = 1; i < (size * UNIT); i++) {
if (i%1024 == 0)
buff[i] = buff[i-1]/8;
else
buff[i] = i/2;
}
pause();
}



更多内容详见微信公众号:Python研究所

Linux占用内存脚本_#include



举报

相关推荐

0 条评论