单列：
"""
判断名企
"""
def get_c_isFamousCompany_clear(x):
x = str(x)
strlist = x.split(',')
for name in strlist:
for s in famousSet:
if x.find(s) != -1:
return 1
return 0
多列：计算年限
def get_c_workyear(x,y):
x = str(x)
y = str(y)
xlist = x.split(',')
ylist = y.split(',')
if len(xlist) != len(ylist):
return 0;
days =0
for i in range(0, len(xlist)):
if ylist[i] =='2888-08-08':
ylist[i]=datetime.now().strftime('%Y-%m-%d')
days = days + (pd.Period(ylist[i], freq="D") - pd.Period(xlist[i], freq="D")).n
days = (int)(days /365) +1
return days
df["isFamous"] =df["company"].fillna(-1).apply(lambda x: get_c_isFamousCompany_clear(x))
df["workyear"] = df.apply(lambda row: get_c_workyearnew(row.c_work_startdate, row.c_work_enddate), axis=1)
