//求1到100之间的奇数的平均值
#include <stdio.h>
int main(void)
{
int i, sum = 0;
float avg = 0;
for (i=1; i<=100; i++)
{
if (i%2 != 0)
{
sum = sum + i;
avg = sum / 10.0;
}
}
printf("奇数的平均值为 %.1f\n",avg);
return 0;
}