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轻量级Web报表工具ActiveReportsJS全新发布v4.0,支持集成更多前端框架!

googlefrank 2023-07-28 阅读 54

当涉及到具体的数据库操作时,我会给出实际的示例,以更清楚地说明每个命令的用法。

创建数据库:

CREATE DATABASE students;

列出数据库:

SHOW DATABASES;

使用数据库:

USE students;

创建表:

CREATE TABLE student_info (
    id INT PRIMARY KEY,
    name VARCHAR(50),
    age INT,
    gender ENUM('男', '女', '未知'),
    course VARCHAR(50)
);

列出表:

SHOW TABLES;

列出表的属性:

SHOW COLUMNS FROM student_info;

列出数据表的详细索引信息:

SHOW INDEX FROM student_info;

显示数据库test中所有表的信息:

SHOW TABLE STATUS FROM test;

显示表名包含test的:

SHOW TABLE STATUS FROM test LIKE '%test%';

插入数据:

INSERT INTO student_info (id, name, age, gender, course) VALUES
(1, '张三男', 21, '男', '数学'),
(2, '张三女', 22, '女', '语文'),
(3, '李四未知', 20, '未知', '英语');

查询数据:

SELECT * FROM student_info;

更新数据:

UPDATE student_info SET course = '语文' WHERE id = 1;

删除数据:

DELETE FROM student_info WHERE id = 3;

条件查询:

SELECT * FROM student_info WHERE age > 20 AND gender = '男';

排序:

SELECT * FROM student_info ORDER BY age DESC;

聚合函数:

SELECT COUNT(*) AS total_students FROM student_info;
SELECT AVG(age) AS avg_age FROM student_info;
SELECT SUM(age) AS total_age FROM student_info;

连接查询:

SELECT student_info.name, student_courses.course_name
FROM student_info
JOIN student_courses ON student_info.course = student_courses.course_name;

假设我们有一个名为"student_courses"的表,它保存课程信息,结构如下:

CREATE TABLE student_courses (
    course_id INT PRIMARY KEY,
    course_name VARCHAR(50)
);

并且表中的数据如下:

INSERT INTO student_courses (course_id, course_name) VALUES
(1, '数学'),
(2, '语文'),
(3, '英语');
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