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算法训练营第56天|LeetCode 583.两个字符串的删除操作 72.编辑距离

WikongGuan 2024-05-08 阅读 4

LeetCode 583.两个字符串的删除操作

题目链接:

LeetCode 583.两个字符串的删除操作

代码:

class Solution {
public:
    int minDistance(string word1, string word2) {
        int size_1 = word1.size();
        int size_2 = word2.size();
        vector<vector<int>>dp(size_1+1,vector<int>(size_2+1,0));
        for (int i = 0; i <= word1.size(); i++) dp[i][0] = i;
        for (int j = 0; j <= word2.size(); j++) dp[0][j] = j;
        for(int i=1;i<=size_1;i++){
            for(int j=1;j<=size_2;j++){
                if(word1[i-1]==word2[j-1]){
                    dp[i][j]=dp[i-1][j-1];
                }
                else{
                    dp[i][j]=min(dp[i][j-1]+1,dp[i-1][j]+1);
                }
            }
        }
        return dp[size_1][size_2];
    }
};

LeetCode 72.编辑距离

题目链接:

LeetCode 72.编辑距离

代码:

class Solution {
public:
    int minDistance(string word1, string word2) {
        int size_1 = word1.size();
        int size_2 = word2.size();
        vector<vector<int>>dp(size_1+1,vector<int>(size_2+1));
        for(int i=0;i<=size_1;i++) dp[i][0] = i;
        for(int j=0;j<=size_2;j++) dp[0][j] = j;
        for(int i=1;i<=size_1;i++){
            for(int j=1;j<=size_2;j++){
                if(word1[i-1]==word2[j-1]) dp[i][j]=dp[i-1][j-1];
                else dp[i][j] = min(min(dp[i][j-1]+1,dp[i-1][j]+1),dp[i-1][j-1]+1);
            }
        }
        return dp[size_1][size_2];
    }
};
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