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arduino中断

zidea 2022-10-17 阅读 81


[codesyntax lang="cpp" lines="normal"]


#define LED 13 #define PIN 2 #define TEST 3 volatile int state = LOW; void setup() { Serial.begin(9600); pinMode(LED, OUTPUT); pinMode(TEST, OUTPUT); attachInterrupt(0, stateChange, CHANGE); } void loop() { int v = digitalRead(PIN); Serial.println(v); delay(500); } void stateChange() { Serial.println("======="); state = !state; digitalWrite(LED, state); if(state) { analogWrite(TEST, 10); } else { analogWrite(TEST, 0); } }


[/codesyntax]

 

备注:

  • 根据本人实验,MJDuino UNO版本有时回因为中断函数的调用导致程序停止运行。


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