文章目录
一、三子棋
平时生活中玩的三子棋游戏。
二、实现
1.玩家和电脑端进行对战
(1)头文件:game.h
(2)测试类:test.c
(3)具体实现类:game.h
test():
#include "game.h"
void menue() {
printf("*******************************************\n");
printf("************* 1. play **************\n");
printf("************* 0. exit **************\n");
printf("*******************************************\n");
}
//判断输赢
//1、玩家赢 2、电脑赢 3、平局
static void if_win(char board[ROW][COL], int row, int col) {
int flag = 1;
for (int i = 0; i <= row; i++) {
for (int j = 0; j < col; j++) {
if (board[i][j] != '*') {
flag = 0;
break;
}
}
}
}
void game() {
char board[ROW][COL] = {0};
//初始化数组
InitBoard(board, ROW, COL);
//打印棋盘
//DisplayBoard(board, ROW, COL);
char ret = 0;
while (1) {
//玩家下棋
player_move(board, ROW, COL);
DisplayBoard(board, ROW, COL);
//判断输赢
ret = is_win(board, ROW, COL);
if (ret != 'C') {
break;
}
//电脑下棋
computer_move(board, ROW, COL);
DisplayBoard(board, ROW, COL);
//判断输赢
ret = is_win(board, ROW, COL);
if (ret != 'C') {
break;
}
}
if (ret == '*') {
printf("玩家赢!\n");
}
else if (ret == '#') {
printf("电脑赢!\n");
}
else {
printf("平局!\n");
}
}
void test() {
int input = 0;
srand ((unsigned int)time(NULL));
do {
menue();
int command;
printf("请选择->");
scanf("%d", &command);
switch (command) {
case 1:
game();
break;
case 0:
printf("退出游戏\n");
break;
default:
printf("请重新输入\n");
}
} while (input);
}
int main() {
test();
return 0;
}
game():
#include "game.h"
//初始化棋盘
void InitBoard(char board[ROW][COL], int row, int col) {
for (int i = 0; i < row; i++) {
for (int j = 0; j < col; j++) {
board[i][j] = ' ';
}
}
}
//打印棋盘
void DisplayBoard(char board[ROW][COL], int row, int col) {
for (int i = 0; i < row; i++) {
for (int j = 0; j < col; j++) {
printf(" %c ", board[i][j]);
if (j < col - 1) {
printf("|");
}
}
printf("\n");
if (i < row - 1) {
for (int j = 0; j < col; j++) {
if (j < col - 1) {
printf("---|");
}
else {
printf("---");
}
}
printf("\n");
}
}
}
//玩家下棋
void player_move(char board[ROW][COL], int row, int col) {
int x, y;
printf("************* 玩家下棋 **************\n");
while (1) {
printf("请输入坐标->");
scanf("%d %d", &x, &y);
if (x >= 1 && y >= 1 && x <= row && y <= col) {
if (board[x-1][y-1] == ' ') {
board[x-1][y-1] = '*';
break;
}
else {
printf("您输入的坐标已被占用,请重新输入\n");
}
}
else {
printf("非法坐标,请重新输入\n");
}
}
}
//电脑下棋
void computer_move(char board[ROW][COL], int row, int col) {
while (1) {
int x = rand() % row;
int y = rand() % col;
if (board[x][y] == ' ') {
board[x][y] = '#';
break;
}
}
}
//判断棋格是否满了
int if_full(char board[ROW][COL], int row, int col) {
for (int i = 0; i < row; i++) {
for (int j = 0; j < col; j++) {
if (board[i][j] == ' ') {
return 0;
}
}
}
return 1;
}
//判断输赢
char is_win(char board[ROW][COL], int row, int col) {
//三种情况赢:行、列、对角线 一种平局:棋盘满了
//判断行
for (int i = 0; i < row; i++) {
if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][0] != ' ') {
return board[i][0];
}
}
//判断列
for (int j = 0; j < col; j++) {
if (board[0][j] == board[1][j] && board[1][j] == board[2][j] && board[0][j] != ' ') {
return board[0][j];
}
}
//判断对角线
if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[0][0] != ' ') {
return board[0][0];
}
if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[0][2] != ' ') {
return board[0][2];
}
//判断平局
if (if_full(board, row, col) == 1) {
return 'Q';
}
else {
return 'C';
}
}
2.展示
总结
多个数的情况下判断行列对角线的情况暂时还没写出来!!!