软件学院oj1093: Above Average

It is said that 90% of frosh expect to be above average in their class. You are to provide a reality check.

The first line of standard input contains an integer C, the number of test cases. C data sets follow. Each data set begins with an integer, N, the number of people in the class (1 <= N <= 1000). N integers follow, separated by spaces or newlines, each giving the final grade (an integer between 0 and 100) of a student in the class. 

For each case you are to output a line giving the percentage of students whose grade is above average, rounded to 3 decimal places.

5 50 50 70 80 100
7 100 95 90 80 70 60 50
3 70 90 80
3 70 90 81
9 100 99 98 97 96 95 94 93 91 

40.000%
57.143%
33.333%
66.667%
55.556% 

#include<iostream>
using namespace std;
#define N 1000 
int main()
{
	int n;
	scanf("%d",&n);
	char a='%';
	for(int i=1;i<=n;i++)
	{
		int m,a[N];
		scanf("%d",&m);
		double average=0,sum=0;
		for(int j=0;j<m;j++)
		{
			scanf("%d",&a[j]);
			sum=sum+a[j];
		}
		average=sum/m*1.0;
		double percent=0;
		for(int k=0;k<m;k++)
		{
			if(a[k]>average)percent++;
		}
		percent=percent/m*100;
		printf("%.3lf",percent);
		cout<<'%'<<endl;
	}
	return 0;
}