/*水的太水了，无力吐槽,%卡了一下就是*/
#include<iostream>
using namespace std;
int main()
{
int n; double a[1001];
cin >> n;
while (n--)
{
double sum = 0;
int m, p = 1;
cin >> m;
while (m--)
{
cin >> a[p++];
sum += a[p - 1];
}
double ave = sum / (p - 1), temp = 0;;
for (int i = 1; i < p; ++i)
{
if (a[i]>ave)
++temp;
}
printf("%.3lf%%\n", temp / (p - 1) * 100); //两个%输出%
}
return 0;
}
/*Description
It is said that 90% of frosh expect to be above average in their class. You are to provide a reality check.
Input
The first line of standard input contains an integer C, the number of test cases. C data sets follow. Each data set begins with an integer, N, the number of people in the class (1 <= N <= 1000). N integers follow, separated by spaces or newlines, each giving the final grade (an integer between 0 and 100) of a student in the class.
Output
For each case you are to output a line giving the percentage of students whose grade is above average, rounded to 3 decimal places.
Sample Input
5
5 50 50 70 80 100
7 100 95 90 80 70 60 50
3 70 90 80
3 70 90 81
9 100 99 98 97 96 95 94 93 91
Sample Output
40.000%
57.143%
33.333%
66.667%
55.556%
*/
