题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=5670
思路:用递归实现输出在后,比较麻烦,保存在数组里,倒着输出数组比较方便
AC代码:
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <algorithm>
#include <queue>
#include <stack>
#include <map>
#include <cstring>
#include <climits>
#include <cmath>
#include <cctype>
const int inf = 0x3f3f3f3f;//1061109567
typedef long long LL;
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
using namespace std;
int deng[35];
int main()
{
int t;
scanf("%d",&t);
while(t--)
{
memset(deng,0,sizeof(deng));
int m;
unsigned long long n;
cin>>m>>n;
int len=0;
while(n!=0)
{
deng[len++] = n % 3;
n /= 3;
}
for(int i=m-1; i>=0; i--)
{
if(deng[i] == 0)
printf("R");
else if(deng[i] == 1)
printf("G");
else if(deng[i] == 2)
printf("B");
}
printf("\n");
}
return 0;
}