poj2104K-th Number （主席树）-CFANZ编程社区

K-th Number Description You are working for Macrohard company in data structures department. After failing your previous task about key insertion you were asked to write a new data structure that would be able to return quickly k-th order statistics in the array segment. That is, given an array a[1...n] of different integer numbers, your program must answer a series of questions Q(i, j, k) in the form: "What would be the k-th number in a[i...j] segment, if this segment was sorted?" For example, consider the array a = (1, 5, 2, 6, 3, 7, 4). Let the question be Q(2, 5, 3). The segment a[2...5] is (5, 2, 6, 3). If we sort this segment, we get (2, 3, 5, 6), the third number is 5, and therefore the answer to the question is 5. Input The first line of the input file contains n --- the size of the array, and m --- the number of questions to answer (1 <= n <= 100 000, 1 <= m <= 5 000). The second line contains n different integer numbers not exceeding 10 ⁹ by their absolute values --- the array for which the answers should be given. The following m lines contain question descriptions, each description consists of three numbers: i, j, and k (1 <= i <= j <= n, 1 <= k <= j - i + 1) and represents the question Q(i, j, k). Output For each question output the answer to it --- the k-th number in sorted a[i...j] segment. Sample Input 7 31 5 2 6 3 7 42 5 34 4 11 7 3 Sample Output 563 Hint This problem has huge input,so please use c-style input(scanf,printf),or you may got time limit exceed. Source Northeastern Europe 2004, Northern Subregion

Time Limit: 20000MS		Memory Limit: 65536K
Total Submissions: 46886		Accepted: 15682
Case Time Limit: 2000MS

[Submit] [Go Back] [Status] [Discuss]

poj2104K-th Number （主席树）_poj2104

Home Page

poj2104K-th Number （主席树）_poj 2104_02

Go Back

poj2104K-th Number （主席树）_i++_03

To top

百度搜索可持久化线段树就出现了这道题

因为很早就知道了主席树可惜一直没有看懂文字无意中在bilibili弹幕网站中看到了讲算法的视频不可思议哈哈

我竟然在B站学算法。。。视频地址

http://www.bilibili.com/video/av4619406

这是文字的讲解

http://seter.is-programmer.com/posts/31907.html

看完视频按照印象。。。AC了

慢慢消化 ~

#include <stdio.h>
#include <vector>
#include <algorithm>
using namespace std;
const int maxn=1e5+5;
struct node
{
  int l,r;
  int sum;  
}T[maxn*40];
int root[maxn],a[maxn],cnt,sum;
vector<int>v;
int getid(int x)
{
  return lower_bound(v.begin(),v.end(),x)-v.begin()+1;
}
void update(int l,int r,int &x,int y,int pos)
{
  T[++cnt]=T[y],T[cnt].sum++,x=cnt;
  if(l==r) return ;
  int mid=(l+r)/2;
  if(mid>=pos) update(l,mid,T[x].l,T[y].l,pos);
  else update(mid+1,r,T[x].r,T[y].r,pos);
}
int query(int l,int r,int x,int y,int k)
{
  if(l==r) return l;
  int mid=(l+r)/2;
  int sum=T[T[y].l].sum-T[T[x].l].sum;
  if(sum>=k) return query(l,mid,T[x].l,T[y].l,k);
  else return query(mid+1,r,T[x].r,T[y].r,k-sum);
}
int main()
{
  int n,m;
  scanf("%d %d",&n,&m);
  for(int i=1;i<=n;i++) 
  scanf("%d",&a[i]),v.push_back(a[i]);
  sort(v.begin(),v.end());
  v.erase(unique(v.begin(),v.end()),v.end());
  for(int i=1;i<=n;i++) 
  update(1,n,root[i],root[i-1],getid(a[i]));
  for(int i=0;i<m;i++)
  {
    int a,b,k;
    scanf("%d %d %d",&a,&b,&k);
    printf("%d\n",v[query(1,n,root[a-1],root[b],k)-1]);
  }
  return 0;
}