hdu An Easy Task

An Easy Task

Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other)

Total Submission(s) : 22   Accepted Submission(s) : 21

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Problem Description

Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?

Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.

Note: if year Y is a leap year, then the 1st leap year is year Y.

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains two positive integers Y and N(1<=N<=10000).

Output

For each test case, you should output the Nth leap year from year Y.

Sample Input

3 2005 25 1855 12 2004 10000

Sample Output

2108

1904

43236

代码：

#include <iostream>
 using namespace std;
 int main()
 {
     int n,m,i,k,l,s;
     cin>>n;
     while(n--)
     {
       cin>>m>>s;
       int year=0;
       for(i=m;s>0;i++)
       {
           if((i%4==0&&i%100!=0)||i%400==0)
           {
           year=i;
           s--;
           }
       }
       cout<<year<<endl;
     }
     return 0;
 }