An Easy Task
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 19908 Accepted Submission(s): 12725
Problem Description
Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?
Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.
Note: if year Y is a leap year, then the 1st leap year is year Y.
Input
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains two positive integers Y and N(1<=N<=10000).
Output
For each test case, you should output the Nth leap year from year Y.
Sample Input
3
2005 25
1855 12
2004 10000
Sample Output
Hint
Author
Ignatius.L
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Y 开始以后的第N个闰年
闰年为能被4整除不能被100整除 或者被400整除
#include <stdio.h>
int main()
{
int ncase;
scanf("%d",&ncase);
while(ncase--)
{
int year,n;
scanf("%d %d",&year,&n);
for(int i=year;;i++)
{
if((i%4==0&&i%100)||i%400==0)
n--;
if(n==0)
{
printf("%d\n",i);
break;
}
}
}
return 0;
}