LeetCode题解(1226)：哲学家进餐(Python)

题目：​​原题链接​​（中等）

标签：多线程

解法一（每个时间只能有一个人吃）：

import threading


class DiningPhilosophers:

    def __init__(self):
        self.lock = threading.Lock()

    # call the functions directly to execute, for example, eat()
    def wantsToEat(self,
                   philosopher: int,
                   pickLeftFork: 'Callable[[], None]',
                   pickRightFork: 'Callable[[], None]',
                   eat: 'Callable[[], None]',
                   putLeftFork: 'Callable[[], None]',
                   putRightFork: 'Callable[[], None]') -> None:
        self.lock.acquire()
        pickLeftFork()
        pickRightFork()
        eat()
        putLeftFork()
        putRightFork()
        self.lock.release()