题目链接:点击打开链接
题目大意:略。
解题思路:略。
AC 代码
-- 解决方案(1)
SELECT s1.gender, s1.day, SUM(s2.score_points) AS total
FROM Scores AS s1, Scores AS s2
WHERE s1.gender = s2.gender AND s1.day >= s2.day
GROUP BY s1.gender, s1.day
ORDER BY s1.gender, s1.day;
-- 解决方案(2)
SELECT gender, day, SUM(score_points) OVER w AS total
FROM Scores
WINDOW w AS (PARTITION BY gender ORDER BY day);
-- 解决方案(3)
SELECT gender, day, SUM(score_points) OVER(PARTITION BY gender ORDER BY gender, day) total
FROM Scores