Description
Every email consists of a local name and a domain name, separated by the @ sign.
For example, in alice@leetcode.com, alice is the local name, and leetcode.com is the domain name.
Besides lowercase letters, these emails may contain '.'s or '+'s.
If you add periods (’.’) between some characters in the local name part of an email address, mail sent there will be forwarded to the same address without dots in the local name. For example, “alice.z@leetcode.com” and “alicez@leetcode.com” forward to the same email address. (Note that this rule does not apply for domain names.)
If you add a plus (’+’) in the local name, everything after the first plus sign will be ignored. This allows certain emails to be filtered, for example m.y+name@email.com will be forwarded to my@email.com. (Again, this rule does not apply for domain names.)
It is possible to use both of these rules at the same time.
Given a list of emails, we send one email to each address in the list. How many different addresses actually receive mails?
Example 1:
Input: ["test.email+alex@leetcode.com","test.e.mail+bob.cathy@leetcode.com","testemail+david@lee.tcode.com"]
Output: 2
Explanation: "testemail@leetcode.com" and "testemail@lee.tcode.com" actually receive mails
Note:
- 1 <= emails[i].length <= 100
- 1 <= emails.length <= 100
- Each emails[i] contains exactly one ‘@’ character.
- All local and domain names are non-empty.
- Local names do not start with a ‘+’ character.
分析
题目的意思是:求email的总个数,email中@前半部分不区分’.’,’+‘后面到‘@’的字符串要删除。我一开始想复杂了,看了答案才发现可以按照’@'分割后分别处理就行了。
代码
class Solution:
def numUniqueEmails(self, emails: List[str]) -> int:
s=set()
for email in emails:
local,domain=email.split('@')
if('+' in local):
local=local[:local.index('+')]
s.add(local.replace('.','')+'@'+domain)
return len(s)
参考文献
[LeetCode] solution